relatable

no only my posts

water

Yes

xOeuf Translated:


"Hm, perhaps."

uh, ok

do you support afghanistan

Yes.

yeah :(

yes

and i can gobble down some nuggets pretty quickly

n w the sweet n sour sauce?? THEM NUGGS BUSSIN

LOL

ماشاءاللہ بھائی کیسے ہو؟ مجھے امید ہے کہ آپ اچھا کر رہے ہوں گے۔ اللہ کے نام سے آپ کی صحت اور خوشی کے لیے دعا گو ہوں انشاء اللہ۔

xOeuf Translated:

"How are you, brother? I hope you are doing well. In the name of Allah, I pray for your health and happiness, God willing."

我為你深深牽掛

谢谢各位公民，请将 17 个比特币发送到我的地址，以便我保释并减少可能被引渡到中国大陆的可能性。

我會盡快進行交易

what the actual-

that's quite the egg head he has o_O

@Arianna ♡ 社會信用高的正人君子

@xOeuf 你没有错

Yes I am hacke

Suppose that f is a continuous function on [0, 2] such that f(0) = f(2). Show that there is a real number ξ ∈ [1, 2] with f(ξ) = f(ξ − 1).

Working:
"f" is continuous on [0,2] . : f(0) = f(2)
. : f(ξ) = f(ξ) - 1
Let g(ξ) = f(ξ) - f(ξ - 1)
Let ξ = 2
g(2) = f(2) - f(1)
g(2) = -(f(1) - f(2))
. : -(f(1) - f(0)) {f(2) = f(1)}
-g(1) {g(1) = f(1) - f(0)}
Let ξu be part of [1,2]
f'(ξu) --> (f(2) - f(1)) / 2 - 1 = g(2)
Thus ξu^-1 in [0,1] is
f'(ξu^-1) = (f(1) - f(0)) / 1 - 0 = g(1)
. : f'(ξu) = -f'(ξu^-1), this shows there is a point where the slope changes between ξu & ξu^-1
The relation g(2) = -g(1) shows that there must exist sum ξ such that f(ξ) - f(ξ-1) = 0.

ok i dont think youve been hacked i just think you've lost your sanity

praise the one above all

:(

Hi, I'd like to introduce you to Miss. Evil Egg
​

cringe

@SpamL

garfielf